4^{x+3}*8^{2x-1}=sqrt(2)

Lösung

4^{x + 3} \cdot 8^{2 x - 1} = 2

x = - \frac{5}{16}

Dezimale

x = - 0.3125

Schritte zur Lösung

4^{x + 3} \cdot 8^{2 x - 1} = 2

Wende Exponentenregel an

2 x - 1 + 7 + 3 (2 x - 1) = \frac{1}{2}

Löse

2 x - 1 + 7 + 3 (2 x - 1) = \frac{1}{2} : x = - \frac{5}{16}

x = - \frac{5}{16}

2^{2 x} + 2^{x} - 12 = 0

e^{x} + x e^{x} = 0

3 (4^{x}) = 4 (5^{2 x - 7})

2^{x - 5} = 3

7 (3^{x}) = 2 (4^{5 x - 4})