4^{1-x}=3^{2x+3}

Lösung

4^{1 - x} = 3^{2 x + 3}

x = - \frac{3 ln ( 3 ) - 2 ln ( 2 )}{2 ln ( 6 )}

Dezimale

x = - 0.53286 \dots

Schritte zur Lösung

4^{1 - x} = 3^{2 x + 3}

Wende Exponentenregel an

(1 - x) ln (4) = (2 x + 3) ln (3)

Löse

(1 - x) ln (4) = (2 x + 3) ln (3) : x = - \frac{3 ln ( 3 ) - 2 ln ( 2 )}{2 ln ( 6 )}

x = - \frac{3 ln ( 3 ) - 2 ln ( 2 )}{2 ln ( 6 )}

ln (2 e^{x} + 1) = - 1

e^{2 x} - 4 = 0

2^{x + 1} + 5 \cdot 2^{x} = 28

2 7^{2 x} = 9^{x - 3}

e^{x} - 5 e^{- x} + 4 e^{- 3 x} = 0