2^{1/2 (x+2)}=3^{x-1}

Lösung

2^{\frac{1}{2} (x + 2)} = 3^{x - 1}

x = \frac{2 ln ( 6 )}{2 ln ( 3 ) - ln ( 2 )}

Dezimale

x = 2.38253 \dots

Schritte zur Lösung

2^{\frac{1}{2} (x + 2)} = 3^{x - 1}

Wende Exponentenregel an

\frac{1}{2} (x + 2) ln (2) = (x - 1) ln (3)

Löse

\frac{1}{2} (x + 2) ln (2) = (x - 1) ln (3) : x = \frac{2 ln ( 6 )}{2 ln ( 3 ) - ln ( 2 )}

x = \frac{2 ln ( 6 )}{2 ln ( 3 ) - ln ( 2 )}

2^{x^{2} - 2 x} = 8

e^{x^{2}} = 0

4^{x} = 10 - 4^{x + 1}

3^{2 x - 1} = 27

e^{2 x} = 9