8(2^{x+1})=2sqrt(2^x)

Lösung

8 (2^{x + 1}) = 2 2^{x}

x = - 6

Schritte zur Lösung

8 (2^{x + 1}) = 2 2^{x}

Wende Exponentenregel an

x + 4 = x \frac{1}{2} + 1

Löse

x + 4 = x \frac{1}{2} + 1 : x = - 6

x = - 6

2^{x + 1} + 2^{x - 1} = 10

e^{2 x} - 2 e^{x} + 1 = 0

5^{x + 1} + 5^{x} + 5^{x - 1} = 775

e^{2 x} = 3

8^{x} = 2