4^{log_{4}(x)+log_{4}(2)}=3

解

4^{l o g_{4} (x) + l o g_{4} (2)} = 3

x = 4^{\frac{l n ( 3 )}{2 l n ( 2 )} - \frac{1}{2}}

十進法表記

x = 1.5

解答ステップ

4^{l o g_{4} (x) + l o g_{4} (2)} = 3

指数の規則を適用する

(lo g_{4} (x) + lo g_{4} (2)) ln (4) = ln (3)

解く

(lo g_{4} (x) + lo g_{4} (2)) ln (4) = ln (3) : x = 4^{\frac{l n ( 3 )}{2 l n ( 2 )} - \frac{1}{2}}

x = 4^{\frac{l n ( 3 )}{2 l n ( 2 )} - \frac{1}{2}}