9^{x+2}=(1/27)^{x-3}

Lösung

9^{x + 2} = (\frac{1}{27})^{x - 3}

x = 1

Schritte zur Lösung

9^{x + 2} = (\frac{1}{27})^{x - 3}

Wende Exponentenregel an

2 (x + 2) = - 3 (x - 3)

Löse

2 (x + 2) = - 3 (x - 3) : x = 1

x = 1

2^{x} = 1.5

4^{x} - 2^{x} - 12 = 0

2 7^{5 x - 4} = 8 1^{7 x - 2}

6 1^{\frac{1}{3}} = k 61

5^{x - 1} = 2 + \frac{3}{5 ^{x - 2}}