4^{2x}=3^{x+1}

Lösung

4^{2 x} = 3^{x + 1}

x = \frac{ln ( 3 )}{4 ln ( 2 ) - ln ( 3 )}

Dezimale

x = 0.65628 \dots

Schritte zur Lösung

4^{2 x} = 3^{x + 1}

Wende Exponentenregel an

2 x ln (4) = (x + 1) ln (3)

Löse

2 x ln (4) = (x + 1) ln (3) : x = \frac{ln ( 3 )}{4 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 3 )}{4 ln ( 2 ) - ln ( 3 )}

4^{x} = 512

e^{y} = 2

e^{y} = 5

e^{y} = 3

3^{x + 2} = 3^{x} + 3^{2}