solvefor t,e^{kt}= 1/2

Lösung

löse nach

t, e^{k t} = \frac{1}{2}

t = - \frac{ln ( 2 )}{k}

Schritte zur Lösung

e^{k t} = \frac{1}{2}

Wende Exponentenregel an

k t = ln (\frac{1}{2})

Löse

k t = ln (\frac{1}{2}) : t = - \frac{ln ( 2 )}{k}

t = - \frac{ln ( 2 )}{k}

2^{x - 3} = \frac{1}{32}

e^{4 x} = 9

8^{2 x + 1} = 1

2^{x - 2} = 16

e^{9 - 4 x} = 2