What is the answer to 4^{x-1}=5 ?

The answer to 4^{x-1}=5 is x=(ln(5))/(2ln(2))+1

Solve for x: 4^{x-1}=5

The solution is x=(ln(5))/(2ln(2))+1

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4^{x - 1} = 5

x = \frac{ln ( 5 )}{2 ln ( 2 )} + 1

Decimal Notation

x = 2.16096 \dots

Solution steps

4^{x - 1} = 5

Apply exponent rules

(x - 1) ln (4) = ln (5)

Solve

(x - 1) ln (4) = ln (5) : x = \frac{ln ( 5 )}{2 ln ( 2 )} + 1

x = \frac{ln ( 5 )}{2 ln ( 2 )} + 1

a, (x^{a})^{b} = b x^{a}

10000 = 40000 e^{- 0.06 t}

1 1^{x} = 1 1^{4} \cdot 1 1^{5}

lo g_{3} (7^{5 x}) = 10

3^{x} = e^{x}

What is the answer to 4^{x-1}=5 ?
The answer to 4^{x-1}=5 is x=(ln(5))/(2ln(2))+1
Solve for x: 4^{x-1}=5
The solution is x=(ln(5))/(2ln(2))+1