4^{x-1}=5

Lösung

4^{x - 1} = 5

x = \frac{ln ( 5 )}{2 ln ( 2 )} + 1

Dezimale

x = 2.16096 \dots

Schritte zur Lösung

4^{x - 1} = 5

Wende Exponentenregel an

(x - 1) ln (4) = ln (5)

Löse

(x - 1) ln (4) = ln (5) : x = \frac{ln ( 5 )}{2 ln ( 2 )} + 1

x = \frac{ln ( 5 )}{2 ln ( 2 )} + 1

so l v e f or a, (x^{a})^{b} = b x^{a}

10000 = 40000 e^{- 0.06 t}

1 1^{x} = 1 1^{4} \cdot 1 1^{5}

lo g_{3} (7^{5 x}) = 10

3^{x} = e^{x}