(1/2)^{x-1}=2^{3x-4}

Lösung

(\frac{1}{2})^{x - 1} = 2^{3 x - 4}

x = \frac{5}{4}

Dezimale

x = 1.25

Schritte zur Lösung

(\frac{1}{2})^{x - 1} = 2^{3 x - 4}

Wende Exponentenregel an

- (x - 1) = 3 x - 4

Löse

- (x - 1) = 3 x - 4 : x = \frac{5}{4}

x = \frac{5}{4}

6^{2 x} = 3 \cdot 2^{x}

so l v e f or x, 2^{x} = 5

9^{x + 4} = 2 7^{x}

2 5^{x + 2} = 5^{3 x - 4}

2^{x + 1} = 1 0^{- x}