6^{x+1}=162*2^x

Lösung

6^{x + 1} = 162 \cdot 2^{x}

x = 3

Schritte zur Lösung

6^{x + 1} = 162 \cdot 2^{x}

Wende Exponentenregel an

(x + 1) ln (6) = ln (162) + x ln (2)

Löse

(x + 1) ln (6) = ln (162) + x ln (2) : x = 3

x = 3

lo g_{5} (2 5^{4 x - 1}) = 3

(\frac{1}{27})^{x} = \frac{1}{3}

4^{x} = 332

2 (2^{2 x}) - 5 (2^{x}) + 2 = 0

4 e^{3 x} = 9