e^{2x+3}=7

Lösung

e^{2 x + 3} = 7

x = \frac{ln ( 7 ) - 3}{2}

Dezimale

x = - 0.52704 \dots

Schritte zur Lösung

e^{2 x + 3} = 7

Wende Exponentenregel an

2 x + 3 = ln (7)

Löse

2 x + 3 = ln (7) : x = \frac{ln ( 7 ) - 3}{2}

x = \frac{ln ( 7 ) - 3}{2}

2 x = 2^{x}

3^{- x + 1} = 9^{x + 2}

4^{x} = 17

4^{x} = 12

4^{x + 2} = 3