9^{x-1}=4

Lösung

9^{x - 1} = 4

x = \frac{ln ( 2 )}{ln ( 3 )} + 1

Dezimale

x = 1.63092 \dots

Schritte zur Lösung

9^{x - 1} = 4

Wende Exponentenregel an

(x - 1) ln (9) = ln (4)

Löse

(x - 1) ln (9) = ln (4) : x = \frac{ln ( 2 )}{ln ( 3 )} + 1

x = \frac{ln ( 2 )}{ln ( 3 )} + 1

2^{3 x - 1} = 4^{x}

3^{x} + 3^{x - 1} - 3^{x - 2} = 11

so l v e f or x, z = e^{x y}

7^{x - 1} = 4 9^{x - 1}

9^{5 x + 2} = (\frac{1}{3})^{11 - x}