What is the answer to 7^{5x+7}=2 ?

The answer to 7^{5x+7}=2 is x=(ln(2)-7ln(7))/(5ln(7))

Solve for x: 7^{5x+7}=2

The solution is x=(ln(2)-7ln(7))/(5ln(7))

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7^{5 x + 7} = 2

x = \frac{ln ( 2 ) - 7 ln ( 7 )}{5 ln ( 7 )}

Decimal Notation

x = - 1.32875 \dots

Solution steps

7^{5 x + 7} = 2

Apply exponent rules

(5 x + 7) ln (7) = ln (2)

Solve

(5 x + 7) ln (7) = ln (2) : x = \frac{ln ( 2 ) - 7 ln ( 7 )}{5 ln ( 7 )}

x = \frac{ln ( 2 ) - 7 ln ( 7 )}{5 ln ( 7 )}

20 (7^{2 x}) = 40 (5^{(3 x + 1)})

2^{2 x + 3} = 8

x, e^{r x} = 0

e^{9 - 4 x} = 8

e^{3 x} = ln (4)

What is the answer to 7^{5x+7}=2 ?
The answer to 7^{5x+7}=2 is x=(ln(2)-7ln(7))/(5ln(7))
Solve for x: 7^{5x+7}=2
The solution is x=(ln(2)-7ln(7))/(5ln(7))