10^{x+3}=5e^{7-x}

Lösung

1 0^{x + 3} = 5 e^{7 - x}

x = \frac{- ln ( 200 ) + 7}{ln ( 10 ) + 1}

Dezimale

x = 0.51525 \dots

Schritte zur Lösung

1 0^{x + 3} = 5 e^{7 - x}

Wende Exponentenregel an

(x + 3) ln (10) = ln (5) + 7 - x

Löse

(x + 3) ln (10) = ln (5) + 7 - x : x = \frac{- ln ( 200 ) + 7}{ln ( 10 ) + 1}

x = \frac{- ln ( 200 ) + 7}{ln ( 10 ) + 1}

15 \cdot 5^{n} = 53 \cdot 2^{n}

a^{x} = b

1 6^{3 x - 1} = 8^{x + 2}

e^{x} = - 4

e^{x} = 16