3^{2x-1}=5

Lösung

3^{2 x - 1} = 5

x = \frac{ln ( 15 )}{2 ln ( 3 )}

Dezimale

x = 1.23248 \dots

Schritte zur Lösung

3^{2 x - 1} = 5

Wende Exponentenregel an

(2 x - 1) ln (3) = ln (5)

Löse

(2 x - 1) ln (3) = ln (5) : x = \frac{ln ( 15 )}{2 ln ( 3 )}

x = \frac{ln ( 15 )}{2 ln ( 3 )}

x 16 = 2

2 7^{3 x - 7} = 9^{6 x - 1}

6 4^{2 x + 4} = 1 6^{5 x}

2^{x + 3} \cdot 2^{- 3 x + 3} = 2

2 7^{x} = \frac{1}{3}