3^x*2^{2x-3}=18

Lösung

3^{x} \cdot 2^{2 x - 3} = 18

x = 2

Schritte zur Lösung

3^{x} \cdot 2^{2 x - 3} = 18

Wende Exponentenregel an

(lo g_{2} (3) x + 2 x - 3) ln (2) = ln (18)

Löse

(lo g_{2} (3) x + 2 x - 3) ln (2) = ln (18) : x = 2

x = 2

4^{x + 1} = \frac{1}{64}

so l v e f or y, x = e^{2 y - 1}

5^{2 x} - 26 \cdot 5^{x} + 25 = 0

9^{x} - 3^{x} = 72

2^{3 x} = 91