4^{x+2}=12

Lösung

4^{x + 2} = 12

x = \frac{ln ( 12 )}{2 ln ( 2 )} - 2

Dezimale

x = - 0.20751 \dots

Schritte zur Lösung

4^{x + 2} = 12

Wende Exponentenregel an

(x + 2) ln (4) = ln (12)

Löse

(x + 2) ln (4) = ln (12) : x = \frac{ln ( 12 )}{2 ln ( 2 )} - 2

x = \frac{ln ( 12 )}{2 ln ( 2 )} - 2

5^{9 x + 5} = 2

so l v e f or y, x = e^{y} - e^{- y}

6 \cdot 2^{\frac{x}{4}} = 222

e^{2 x} + e^{x} = 0

6^{4 x - 9} = (\frac{1}{36})^{x - 4}