4^x=3^{x+1}

Lösung

4^{x} = 3^{x + 1}

x = \frac{ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

Dezimale

x = 3.81884 \dots

Schritte zur Lösung

4^{x} = 3^{x + 1}

Wende Exponentenregel an

x ln (4) = (x + 1) ln (3)

Löse

x ln (4) = (x + 1) ln (3) : x = \frac{ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 3 )}{2 ln ( 2 ) - ln ( 3 )}

(\frac{1}{8})^{- 3 a} = 51 2^{3 a}

5^{x + 1} = 70

e^{x} - x e^{x} = 0

1 0^{x} + 1 0^{x + 1} = 22

e^{x} = x^{3}