2^{3x+2}=6

Lösung

2^{3 x + 2} = 6

x = \frac{ln ( \frac{3}{2} )}{3 ln ( 2 )}

Dezimale

x = 0.19498 \dots

Schritte zur Lösung

2^{3 x + 2} = 6

Wende Exponentenregel an

(3 x + 2) ln (2) = ln (6)

Löse

(3 x + 2) ln (2) = ln (6) : x = \frac{ln ( \frac{3}{2} )}{3 ln ( 2 )}

x = \frac{ln ( \frac{3}{2} )}{3 ln ( 2 )}

1 0^{x + 2} - 12 = 22

2^{x} = A^{\frac{x}{12}}

86 \cdot 1 0^{\frac{x}{4}} = 41

8^{x + 6} = 5^{x}

\frac{16 e ^{4 x - 8}}{e ^{16} - 1} = 0