27^{x+2}=(1/9)^{2x+4}

Lösung

2 7^{x + 2} = (\frac{1}{9})^{2 x + 4}

x = - 2

Schritte zur Lösung

2 7^{x + 2} = (\frac{1}{9})^{2 x + 4}

Wende Exponentenregel an

3 (x + 2) = - 2 (2 x + 4)

Löse

3 (x + 2) = - 2 (2 x + 4) : x = - 2

x = - 2

5^{x + 3} = \frac{1}{5}

3^{2 x - 1} = 4^{3 x}

so l v e f or x, 2^{x} - 2^{y} = 2016

4^{x + 2} = 7^{x - 1}

5^{x + 7} = 3