49^{x+1}=7

Lösung

4 9^{x + 1} = 7

x = - \frac{1}{2}

Dezimale

x = - 0.5

Schritte zur Lösung

4 9^{x + 1} = 7

Wende Exponentenregel an

2 (x + 1) = 1

Löse

2 (x + 1) = 1 : x = - \frac{1}{2}

x = - \frac{1}{2}

\frac{2 ^{x} + 1}{2 ^{x} - 1} = 5

e^{t} = 0

e^{[2 l n (x) - l n (x^{2} + x - 3)]} = 1

0. 5^{x} = 0.25

so l v e f or x, 2 e^{- 2 x} = 5