64^{x-1}=4^{x+2}

Lösung

6 4^{x - 1} = 4^{x + 2}

x = \frac{5}{2}

Dezimale

x = 2.5

Schritte zur Lösung

6 4^{x - 1} = 4^{x + 2}

Wende Exponentenregel an

3 (x - 1) = x + 2

Löse

3 (x - 1) = x + 2 : x = \frac{5}{2}

x = \frac{5}{2}

so l v e f or x, e^{y} = e^{x} + c

3^{x + 1} = 243

5^{5 x - 1} = 3^{1 - 2 x}

so l v e f or n, (x y)^{n} = x^{n} y^{n}

e^{x - 2} + 10 = 3