4^{x+2}=\sqrt[3]{16^{x+5}}

Lösung

4^{x + 2} = 3 1 6^{x + 5}

x = 4

Schritte zur Lösung

4^{x + 2} = 3 1 6^{x + 5}

Wende Exponentenregel an

x + 2 = \frac{2}{3} (x + 5)

Löse

x + 2 = \frac{2}{3} (x + 5) : x = 4

x = 4

3^{1 - 2 x} = \frac{1}{9}

2 5^{x - 4} = (\frac{1}{5})^{2 x}

0 = x e^{x}

3^{2 x - 1} = \frac{1}{243}

2^{5 x + 8} = (\frac{1}{32})^{3}