10^{4x+1}=132

Lösung

1 0^{4 x + 1} = 132

x = \frac{ln ( \frac{66}{5} )}{4 ln ( 10 )}

Dezimale

x = 0.28014 \dots

Schritte zur Lösung

1 0^{4 x + 1} = 132

Wende Exponentenregel an

(4 x + 1) ln (10) = ln (132)

Löse

(4 x + 1) ln (10) = ln (132) : x = \frac{ln ( \frac{66}{5} )}{4 ln ( 10 )}

x = \frac{ln ( \frac{66}{5} )}{4 ln ( 10 )}

4^{x} - 6 \cdot 2^{x} - 16 = 0

ln (e^{t^{2} - t}) = 6

5 x^{3} e^{x} = 2 x e^{x}

2^{8 x + 5} = 8^{x^{2} - 2}

e^{x} e^{x + 1} = 10