2^{x+1}=13

Lösung

2^{x + 1} = 13

x = \frac{ln ( 13 )}{ln ( 2 )} - 1

Dezimale

x = 2.70043 \dots

Schritte zur Lösung

2^{x + 1} = 13

Wende Exponentenregel an

(x + 1) ln (2) = ln (13)

Löse

(x + 1) ln (2) = ln (13) : x = \frac{ln ( 13 )}{ln ( 2 )} - 1

x = \frac{ln ( 13 )}{ln ( 2 )} - 1

so l v e f or x, h = 2^{x} - 1

5^{x - 1} + 5^{x - 2} = 30

5^{x + 4} \cdot 25 = 125

130 (5^{x - 2}) = 1 + 2 5^{x}

(\frac{3}{5})^{x} = 7^{1 - x}