2^{x+1}=9

Lösung

2^{x + 1} = 9

x = \frac{2 ln ( 3 )}{ln ( 2 )} - 1

Dezimale

x = 2.16992 \dots

Schritte zur Lösung

2^{x + 1} = 9

Wende Exponentenregel an

(x + 1) ln (2) = ln (9)

Löse

(x + 1) ln (2) = ln (9) : x = \frac{2 ln ( 3 )}{ln ( 2 )} - 1

x = \frac{2 ln ( 3 )}{ln ( 2 )} - 1

3 \cdot 2^{x} = 24

e^{l n (2 x)} = 6

7^{x + 1} - 7^{x} = 42

e^{3 - x} = 1

4 9^{m + 1} = 7