4*2^x=2^{6x+3}

Lösung

4 \cdot 2^{x} = 2^{6 x + 3}

x = - \frac{1}{5}

Dezimale

x = - 0.2

Schritte zur Lösung

4 \cdot 2^{x} = 2^{6 x + 3}

Wende Exponentenregel an

x + 2 = 6 x + 3

Löse

x + 2 = 6 x + 3 : x = - \frac{1}{5}

x = - \frac{1}{5}

9^{2 - x} = (\frac{1}{3})^{2 x + 1}

(\frac{1}{4})^{x} = 4

(2)^{k} = 0.25

3^{2 x} - 10 (3^{x}) + 9 = 0

9^{x} = 2 7^{- 6}