16^{x+1}=8^{2x+1}

Lösung

1 6^{x + 1} = 8^{2 x + 1}

x = \frac{1}{2}

Dezimale

x = 0.5

Schritte zur Lösung

1 6^{x + 1} = 8^{2 x + 1}

Wende Exponentenregel an

4 (x + 1) = 3 (2 x + 1)

Löse

4 (x + 1) = 3 (2 x + 1) : x = \frac{1}{2}

x = \frac{1}{2}

4 8^{x - 5} = 4^{4 + 2 x}

e^{x} - x^{3} = 0

4^{3 x} = 8^{x - 1}

e^{x} - 2 e^{- x} = 1

e^{5 x} = 4