-3<= x-2<1

The solution to -3<= x-2<1 is -1<= x<3

Solution

- 3 \leq x - 2 < 1

- 1 \leq x < 3

Interval Notation

[- 1, 3)

Solution steps

- 3 \leq x - 2 < 1

a \leq u < b

then

a \leq u and u < b

- 3 \leq x - 2 and x - 2 < 1

- 3 \leq x - 2 : x \geq - 1

x - 2 < 1 : x < 3

Combine the intervals

x \geq - 1 and x < 3

Merge Overlapping Intervals

- 1 \leq x < 3

3 x + 5 = 5 x - 9

\frac{x ^{\frac{5}{6}}}{x ^{\frac{1}{6}}}

\frac{( 3 \cdot 1 0 ^{8} )}{9}

\frac{4 ( k ) ^{4}}{3 k ^{9}}

12 x^{2} - 132 x + 216