27=10^{x+4}

Lösung

27 = 1 0^{x + 4}

x = \frac{3 ln ( 3 )}{ln ( 10 )} - 4

Dezimale

x = - 2.56863 \dots

Schritte zur Lösung

27 = 1 0^{x + 4}

Wende Exponentenregel an

ln (27) = (x + 4) ln (10)

Löse

ln (27) = (x + 4) ln (10) : x = \frac{3 ln ( 3 )}{ln ( 10 )} - 4

x = \frac{3 ln ( 3 )}{ln ( 10 )} - 4

2 (7^{y}) = 3 - 5 7^{y}

- 2 = 2^{x}

16 = 5 + 16 e^{34 k}

3^{y} = \frac{1}{81}

3^{2 x} - 6 \cdot 3^{x} + 8 = 0