(sqrt(3))^x=729

Lösung

(3)^{x} = 729

x = 12

Schritte zur Lösung

(3)^{x} = 729

Wende Exponentenregel an

\frac{1}{2} x = 6

Löse

\frac{1}{2} x = 6 : x = 12

x = 12

2^{x + 3} = 4^{x}

so l v e f or T, x^{T} A^{T} A x = 0

7^{3 x + 1} = 40

3^{2 x + 2} + 2 7^{x + 1} = 36

2^{x} + 2^{- x} = \frac{65}{8}