5^{x(-2x+1)}= 1/5

Lösung

5^{x (- 2 x + 1)} = \frac{1}{5}

x = - \frac{1}{2}, x = 1

Dezimale

x = - 0.5, x = 1

Schritte zur Lösung

5^{x (- 2 x + 1)} = \frac{1}{5}

Wende Exponentenregel an

x (- 2 x + 1) = - 1

Löse

x (- 2 x + 1) = - 1 : x = - \frac{1}{2}, x = 1

x = - \frac{1}{2}, x = 1

0 = - 2^{2 - b} + 2

2^{x + 2} + 2^{x} = 40

2^{2 x} = 8^{x - 1}

22 = 100 - 80 e^{x}

3^{2 x + 1} - 5 = 16