e^{x+2}=2k+1

Lösung

e^{x + 2} = 2 k + 1

x = ln (2 k + 1) - 2

Schritte zur Lösung

e^{x + 2} = 2 k + 1

Wende Exponentenregel an

x + 2 = ln (2 k + 1)

Löse

x + 2 = ln (2 k + 1) : x = ln (2 k + 1) - 2

x = ln (2 k + 1) - 2

so l v e f or x, a = 6 4^{x} 4^{y}

2 7^{x + 2} = 9^{6 x + 10}

b^{7 - x} = b^{3}

12 5^{x + 1} = 25

\frac{1}{2} = e^{- t}