(\sqrt[5]{7})^x=7^{2x+3}

Lösung

(57)^{x} = 7^{2 x + 3}

x = - \frac{5}{3}

Dezimale

x = - 1.66666 \dots

Schritte zur Lösung

(57)^{x} = 7^{2 x + 3}

Wende Exponentenregel an

\frac{1}{5} x = 2 x + 3

Löse

\frac{1}{5} x = 2 x + 3 : x = - \frac{5}{3}

x = - \frac{5}{3}

e^{3 x - 5} = 13

2^{x + 2} = 8^{x - 2}

e^{2 x} = \frac{1}{32}

2^{a} = 10

2^{x - 2} = 32