10^{2x+3}=5

Lösung

1 0^{2 x + 3} = 5

x = - \frac{ln ( 200 )}{2 ln ( 10 )}

Dezimale

x = - 1.15051 \dots

Schritte zur Lösung

1 0^{2 x + 3} = 5

Wende Exponentenregel an

(2 x + 3) ln (10) = ln (5)

Löse

(2 x + 3) ln (10) = ln (5) : x = - \frac{ln ( 200 )}{2 ln ( 10 )}

x = - \frac{ln ( 200 )}{2 ln ( 10 )}

2^{n - 6} = 8^{2 - n}

2^{2 x} - 3 \cdot 2^{x + 1} + 8 = 0

4^{x - x^{2}} = \frac{1}{2}

4^{x} + 6^{x} - 2 \cdot 9^{x} = 0

2 7^{x + 3} = 9^{2 x}