2^{(3x^3+11x^2-4x)}=1

Lösung

2^{(3 x^{3} + 11 x^{2} - 4 x)} = 1

x = 0, x = \frac{1}{3}, x = - 4

Dezimale

x = 0, x = 0.33333 \dots, x = - 4

Schritte zur Lösung

2^{(3 x^{3} + 11 x^{2} - 4 x)} = 1

Wende Exponentenregel an

(3 x^{3} + 11 x^{2} - 4 x) ln (2) = ln (1)

Löse

(3 x^{3} + 11 x^{2} - 4 x) ln (2) = ln (1) : x = 0, x = \frac{1}{3}, x = - 4

x = 0, x = \frac{1}{3}, x = - 4

8^{x} \cdot 4^{2 x - 1} = 32

so l v e f or n, (1 - 0.01)^{n} = 0.01

4 \cdot 5^{x} - 3 = 7

8 1^{x} = \frac{1}{27}

8^{5 - x} = 3