11^{x-5}=7^{x-5}

Lösung

1 1^{x - 5} = 7^{x - 5}

x = \frac{- 5 ln ( 7 ) + 5 ln ( 11 )}{ln ( 11 ) - ln ( 7 )}

Dezimale

x = 5

Schritte zur Lösung

1 1^{x - 5} = 7^{x - 5}

Wende Exponentenregel an

(x - 5) ln (11) = (x - 5) ln (7)

Löse

(x - 5) ln (11) = (x - 5) ln (7) : x = \frac{- 5 ln ( 7 ) + 5 ln ( 11 )}{ln ( 11 ) - ln ( 7 )}

x = \frac{- 5 ln ( 7 ) + 5 ln ( 11 )}{ln ( 11 ) - ln ( 7 )}

3^{n + 1} + 3^{n + 2} + 3^{n + 3} = 351

0 = e^{2 x} - 4

3 \cdot 4^{x} = 21

7^{2 x} = 0.18

3 e^{x + 2} = 12