3^{x+2}=2^x

Lösung

3^{x + 2} = 2^{x}

x = - \frac{2 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

Dezimale

x = - 5.41902 \dots

Schritte zur Lösung

3^{x + 2} = 2^{x}

Wende Exponentenregel an

(x + 2) ln (3) = x ln (2)

Löse

(x + 2) ln (3) = x ln (2) : x = - \frac{2 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

x = - \frac{2 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

9^{x + 10} + 3 = 81

2. 3^{x - 2} = 162

6 e^{x + 3} - 4 = 20

(\frac{1}{2})^{4 x} = 16

9^{2 x + 1} = 2 7^{x}