32^{3x+4}=128^{2x+3}

Lösung

3 2^{3 x + 4} = 12 8^{2 x + 3}

x = 1

Schritte zur Lösung

3 2^{3 x + 4} = 12 8^{2 x + 3}

Wende Exponentenregel an

5 (3 x + 4) = 7 (2 x + 3)

Löse

5 (3 x + 4) = 7 (2 x + 3) : x = 1

x = 1

1^{x} = 4

1^{x} = 3

so l v e f or x, f = (\frac{1}{3})^{x}

x^{2 l o g_{3} (x)} = 9

1 - 2^{x} = 0