What is the answer to 3*6^{x-1}=2*3^{x+2} ?

The answer to 3*6^{x-1}=2*3^{x+2} is x=(2ln(6))/(ln(2))

Solve for x: 3*6^{x-1}=2*3^{x+2}

The solution is x=(2ln(6))/(ln(2))

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3 \cdot 6^{x - 1} = 2 \cdot 3^{x + 2}

x = \frac{2 ln ( 6 )}{ln ( 2 )}

Decimal Notation

x = 5.16992 \dots

Solution steps

3 \cdot 6^{x - 1} = 2 \cdot 3^{x + 2}

Apply exponent rules

ln (3) + (x - 1) ln (6) = ln (2) + (x + 2) ln (3)

Solve

ln (3) + (x - 1) ln (6) = ln (2) + (x + 2) ln (3) : x = \frac{2 ln ( 6 )}{ln ( 2 )}

x = \frac{2 ln ( 6 )}{ln ( 2 )}

21 6^{x + 4} = (\frac{1}{36})^{x - 1}

C = 100 \cdot 2^{\frac{t}{15}}

1 2^{m + 3} = (\frac{1}{3})^{2 m}

3^{2 x - 8} = 81

5^{x + 2} + 3 \cdot 5^{x + 1} - 8 = 0

What is the answer to 3*6^{x-1}=2*3^{x+2} ?
The answer to 3*6^{x-1}=2*3^{x+2} is x=(2ln(6))/(ln(2))
Solve for x: 3*6^{x-1}=2*3^{x+2}
The solution is x=(2ln(6))/(ln(2))