12^{x-2}=20

Lösung

1 2^{x - 2} = 20

x = \frac{ln ( 20 )}{ln ( 12 )} + 2

Dezimale

x = 3.20557 \dots

Schritte zur Lösung

1 2^{x - 2} = 20

Wende Exponentenregel an

(x - 2) ln (12) = ln (20)

Löse

(x - 2) ln (12) = ln (20) : x = \frac{ln ( 20 )}{ln ( 12 )} + 2

x = \frac{ln ( 20 )}{ln ( 12 )} + 2

4 9^{x} - 8 \cdot 7^{x} + 7 = 0

0.0 1^{(3 x - 1)} = 0.0 1^{0} AA

5^{m + 4} = 6

16 = 5 + 16 e^{k (34)}

(\frac{1}{27})^{x} = 9^{x + 5}