9^x=(1/3)^{x^2-x}

Lösung

9^{x} = (\frac{1}{3})^{x^{2} - x}

x = - 1, x = 0

Schritte zur Lösung

9^{x} = (\frac{1}{3})^{x^{2} - x}

Wende Exponentenregel an

2 x = - (x^{2} - x)

Löse

2 x = - (x^{2} - x) : x = - 1, x = 0

x = - 1, x = 0

e^{3 x} = 2 (e^{x})

x e^{2 x} + 3 e x^{2} e^{2 x} = 0

1.0 5^{t} = 4.35

2^{3 - 2 x} = \frac{1}{8}

3^{x + 2} = 5^{2 x - 1}