3^{2x+1}=4^{x-2}

Lösung

3^{2 x + 1} = 4^{x - 2}

x = - \frac{ln ( 48 )}{2 ( ln ( 3 ) - ln ( 2 ) )}

Dezimale

x = - 4.77377 \dots

Schritte zur Lösung

3^{2 x + 1} = 4^{x - 2}

Wende Exponentenregel an

(2 x + 1) ln (3) = (x - 2) ln (4)

Löse

(2 x + 1) ln (3) = (x - 2) ln (4) : x = - \frac{ln ( 48 )}{2 ( ln ( 3 ) - ln ( 2 ) )}

x = - \frac{ln ( 48 )}{2 ( ln ( 3 ) - ln ( 2 ) )}

1.3345 = e^{7.25 x}

2^{x + 3} = 0

5^{2 x} + 125 = 6 \cdot 5^{x + 1}

3^{3 x + 4} = 21

3^{3 x + 4} = 12