5^{2x-4}=125

Lösung

5^{2 x - 4} = 125

x = \frac{7}{2}

Dezimale

x = 3.5

Schritte zur Lösung

5^{2 x - 4} = 125

Wende Exponentenregel an

2 x - 4 = 3

Löse

2 x - 4 = 3 : x = \frac{7}{2}

x = \frac{7}{2}

so l v e f or x, t (x) = 2. 3^{x - 1.5}

4^{x - 2} = 3

1 8^{2 x - 3} = 2 0^{x + 1}

\frac{2 ^{x - 3}}{4 ^{1 - x}} = 1

12 \cdot 1.1 7^{t} = 56