49^{x+3}=7^{x^2-3x+8}

Lösung

4 9^{x + 3} = 7^{x^{2} - 3 x + 8}

x = \frac{5 + 17}{2}, x = \frac{5 - 17}{2}

Dezimale

x = 4.56155 \dots, x = 0.43844 \dots

Schritte zur Lösung

4 9^{x + 3} = 7^{x^{2} - 3 x + 8}

Wende Exponentenregel an

2 (x + 3) = x^{2} - 3 x + 8

Löse

2 (x + 3) = x^{2} - 3 x + 8 : x = \frac{5 + 17}{2}, x = \frac{5 - 17}{2}

x = \frac{5 + 17}{2}, x = \frac{5 - 17}{2}

8^{x} = 360000000

7^{q} = 49

2000 = 1000 e^{0.09 x}

4^{x} = 1 6^{2 x + 9}

(0.1)^{- 4 x + 5} = 100