What is the answer to 3^x=9\sqrt[5]{27} ?

The answer to 3^x=9\sqrt[5]{27} is x= 13/5

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3^x=9\sqrt[5]{27}

x = \frac{13}{5}

Decimal Notation

x = 2.6

Solution steps

Apply exponent rules

x = \frac{13}{5}

x, 4 e^{2 x + 3} = 7 e^{3 x - 2}

5^{x} = 87

4^{2 x} = 3 2^{\frac{1}{2}}

5^{2 x} - 5^{x} + 1 = 0

What is the answer to 3^x=9\sqrt[5]{27} ?
The answer to 3^x=9\sqrt[5]{27} is x= 13/5
Solve for x: 3^x=9\sqrt[5]{27}
The solution is x= 13/5