7^{x+2}=410

Lösung

7^{x + 2} = 410

x = \frac{ln ( 410 )}{ln ( 7 )} - 2

Dezimale

x = 1.09169 \dots

Schritte zur Lösung

7^{x + 2} = 410

Wende Exponentenregel an

(x + 2) ln (7) = ln (410)

Löse

(x + 2) ln (7) = ln (410) : x = \frac{ln ( 410 )}{ln ( 7 )} - 2

x = \frac{ln ( 410 )}{ln ( 7 )} - 2

2^{3 x - 6} = 2^{x - 3}

1536 = 3 (2)^{n - 1}

3^{- 5 x} = 81

7^{x + 1} = 0

so l v e f or x, e^{x} = 8