27^{x-1}=3^{x+5}

Lösung

2 7^{x - 1} = 3^{x + 5}

x = 4

Schritte zur Lösung

2 7^{x - 1} = 3^{x + 5}

Wende Exponentenregel an

3 (x - 1) = x + 5

Löse

3 (x - 1) = x + 5 : x = 4

x = 4

25000 = 50000 (0.9)^{x - 1}

5^{4 x + 2} = 7^{x + 5}

2^{2 x} + 2^{x + 2} = 32

9^{x} - 16 \cdot 3^{x} + 27 = 0

3 e^{x} - x e^{x} = 0