5^{x+3}=\sqrt[4]{25^{x+5}}

Lösung

5^{x + 3} = 4 2 5^{x + 5}

x = - 1

Schritte zur Lösung

5^{x + 3} = 4 2 5^{x + 5}

Wende Exponentenregel an

x + 3 = \frac{1}{2} (x + 5)

Löse

x + 3 = \frac{1}{2} (x + 5) : x = - 1

x = - 1

4^{2 x} - 6 \cdot 4^{2 x} = - 20

2500 = 2000 (1.04)^{x}

lo g_{10} (3^{x}) = 81

1 5^{- 3 y} = 9

so l v e f or y, z = x e^{x^{2} y}